The number of tetrahedral voids present in 0. | vedclass

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(C) In a hexagonal closed packing $(HCP)$ structure,the number of atoms per unit cell is $Z = 6$.The number of tetrahedral voids $(TV)$ is given by $2

Vedclass · Accepted Answer

$3.6 	imes 10^{24}$

Vedclass · Answer

(C) In a hexagonal closed packing $(HCP)$ structure,the number of atoms per unit cell is $Z = 6$.The number of tetrahedral voids $(TV)$ is given by $2 	imes Z$.So,$TV = 2 	imes 6 = 12$ per unit cell.For $1 	ext{ mole}$ of $HCP$ structure,the number of tetrahedral voids is $12 	imes N_A$.For $0.5 	ext{ mole}$ of $HCP$ structure,the number of tetrahedral voids is $12 	imes 0.5 	imes N_A = 6 	imes N_A$.Substituting $N_A = 6.022 	imes 10^{23} 	ext{ mol}^{-1}$:$6 	imes 6.022 	imes 10^{23} = 3.6132 	imes 10^{24} \approx 3.6 	imes 10^{24}$.

The number of tetrahedral voids present in $0.5 \text{ mole}$ of $HCP$ crystal structure is:

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