The third ionization energy is maximum for

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(D) The electronic configuration of Boron $(Z=5)$ is $1s^2 2s^2 2p^1$. After losing $3$ electrons,Boron attains the stable noble gas configuration of

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Boron

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(D) The electronic configuration of Boron $(Z=5)$ is $1s^2 2s^2 2p^1$. After losing $3$ electrons,Boron attains the stable noble gas configuration of Helium $(1s^2)$. Removing the third electron from Boron requires breaking the stable $2s^2$ shell,which involves a very high amount of energy compared to the other elements listed. Therefore,Boron has the maximum third ionization energy.

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