The three ships namely A,B and C sail from In | vedclass

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(A) The probability that ship $A$ reaches safely is $P(A) = \frac{2}{2+5} = \frac{2}{7}$.The probability that ship $B$ reaches safely is $P(B) = \frac

Vedclass · Accepted Answer

$\frac{18}{595}$

Vedclass · Answer

(A) The probability that ship $A$ reaches safely is $P(A) = \frac{2}{2+5} = \frac{2}{7}$.The probability that ship $B$ reaches safely is $P(B) = \frac{3}{3+7} = \frac{3}{10}$.The probability that ship $C$ reaches safely is $P(C) = \frac{6}{6+11} = \frac{6}{17}$.Since the events are independent,the probability that all of them arrive safely is $P(A \cap B \cap C) = P(A) 	imes P(B) 	imes P(C)$.$P(A \cap B \cap C) = \frac{2}{7} 	imes \frac{3}{10} 	imes \frac{6}{17} = \frac{36}{1190} = \frac{18}{595}$.

The three ships namely $A$,$B$ and $C$ sail from India to Africa. If the odds in favour of the ships reaching safely are $2:5$,$3:7$ and $6:11$ respectively,then the probability of all of them arriving safely is

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