The total maximum number of electrons possible in $3d$,$6d$,$5s$,and $4f$ orbitals with $m_l$ (magnetic quantum number) value $-2$ is

  • A
    $6$
  • B
    $8$
  • C
    $10$
  • D
    $12$

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Similar Questions

Correct set of four quantum numbers for the outermost electron of rubidium $(Z=37)$ is :

The ground state term symbol for an electronic state is governed by

Describe the orbitals with the following quantum numbers using $s, p, d, f$ notations:
$(a) \ n = 2, l = 1$
$(b) \ n = 4, l = 0$
$(c) \ n = 5, l = 3$
$(d) \ n = 3, l = 2$

Match the quantum numbers with the information provided:
Quantum Number Information
$(1)$ Principal quantum number $(A)$ Spatial orientation of the orbital
$(2)$ Azimuthal quantum number $(B)$ Energy and size of the orbital
$(3)$ Magnetic quantum number $(C)$ Electron spin
$(4)$ Spin quantum number $(D)$ Shape of the orbital

The electronic configuration $1s^2, 2s^2 2p^5, 3s^1$ represents:

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