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(A) The current $i$ is given by $i = neAv_d$,where $n$ is the number density of electrons,$e$ is the charge of an electron,$A$ is the cross-sectional

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$91 	imes 10^{-12}\, kg\, m/s$

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(A) The current $i$ is given by $i = neAv_d$,where $n$ is the number density of electrons,$e$ is the charge of an electron,$A$ is the cross-sectional area,and $v_d$ is the drift velocity.The total number of electrons $N$ in a wire of length $L$ is $N = nAL$.Thus,$nA = N/L$.Substituting this into the current equation: $i = (N/L)ev_d$,which implies $Nv_d = iL/e$.The total momentum $P$ of all electrons is $P = Nmv_d$,where $m$ is the mass of an electron $(m \approx 9.1 	imes 10^{-31}\, kg)$.Substituting $Nv_d = iL/e$ into the momentum equation: $P = m(iL/e) = (m/e) 	imes iL$.Given $m = 9.1 	imes 10^{-31}\, kg$,$e = 1.6 	imes 10^{-19}\, C$,$i = 16\, A$,and $L = 1\, m$:$P = (9.1 	imes 10^{-31} / 1.6 	imes 10^{-19}) 	imes 16 	imes 1$$P = (9.1 / 1.6) 	imes 10^{-12} 	imes 16$$P = 9.1 	imes 10^{-12} 	imes 10 = 91 	imes 10^{-12}\, kg\, m/s$.

The total momentum of electrons in a straight wire of copper of length $1\, m$ carrying a current of $16\, A$ is

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