The total number of alkenes possible by dehydrobromination of $3$-bromo-$3$-cyclopentylhexane using alcoholic $KOH$ is

The reaction $R-CH=CH_2 \xrightarrow{Na/NH_3, C_2H_5OH} R-CH_2CH_3$ is known as:

Reaction $(1): CH_3-CH=CH-CH_3$ $\xrightarrow{\text{Cold } KMnO_4} (A)$ $\xrightarrow{NaIO_4} (B)$ ($2$ moles)
Reaction $(2): CH_3-CH=CH-CH_3 \xrightarrow{KMnO_4/NaIO_4} (C)$ ($2$ moles)
Product $(B)$ and $(C)$ respectively are:

How many products will be formed in this reaction?

Which of the following has the lowest heat of hydrogenation per mole?

$Ph-CH=CH_2 \xrightarrow[HBr]{(PhCOO)_2} \text{Product}$
Consider the above reaction:
$A$. The reaction proceeds through a more stable radical intermediate.
$B$. The role of peroxide is to generate $\dot{H}$ (Hydrogen radical).
$C$. During this reaction, benzene is formed as a byproduct.
$D$. $1-\text{Bromo}-2-\text{phenylethane}$ is formed as the minor product.
$E$. The same reaction in the absence of peroxide proceeds via a carbocation intermediate.
Identify the correct statements. Choose the correct answer from the options given below: