The total number of geometrical isomers possi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Geometrical isomerism arises in heteroleptic complexes due to different possible geometric arrangements of ligands around the central metal atom.F

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(C) Geometrical isomerism arises in heteroleptic complexes due to different possible geometric arrangements of ligands around the central metal atom.For an octahedral complex of the type $[MA_{2}B_{2}C_{2}]$,there are $5$ possible geometrical isomers.These isomers correspond to the different relative positions of the pairs of ligands $A, B,$ and $C$ (trans or cis to each other).

The total number of geometrical isomers possible for an octahedral complex of the type $[MA_{2}B_{2}C_{2}]$ is ($M=$ transition metal; $A, B$ and $C$ are monodentate ligands).

Similar Questions

The value of $1$ Bohr magneton $(\mu_B)$ is equal to ......... $A \cdot m^2$.

The correct statement about the magnetic properties of $[Fe(CN)_6]^{3-}$ and $[FeF_6]^{3-}$ is

$[Cr(NH_3)_6]^{3+}$ is paramagnetic while $[Ni(CN)_4]^{2-}$ is diamagnetic. Explain why?

Which of the following complexes exhibits optical isomerism?

The two complexes given below are $............$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module