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(C) The formula for the maximum line-of-sight distance $d$ between a transmitting antenna of height $h_T$ and a receiving antenna of height $h_R$ is g

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$20$

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(C) The formula for the maximum line-of-sight distance $d$ between a transmitting antenna of height $h_T$ and a receiving antenna of height $h_R$ is given by $d = \sqrt{2Rh_T} + \sqrt{2Rh_R}$, where $R$ is the radius of the Earth.Given: $h_T = 45 \ m = 0.045 \ km$, $d = 40 \ km$, and $R = 6400 \ km$.Substituting the values into the formula:$40 = \sqrt{2 	imes 6400 	imes 0.045} + \sqrt{2 	imes 6400 	imes h_R}$$40 = \sqrt{12800 	imes 0.045} + \sqrt{12800 	imes h_R}$$40 = \sqrt{576} + \sqrt{12800 	imes h_R}$$40 = 24 + \sqrt{12800 	imes h_R}$$16 = \sqrt{12800 	imes h_R}$Squaring both sides:$256 = 12800 	imes h_R$$h_R = \frac{256}{12800} \ km = 0.02 \ km$Converting to meters: $h_R = 0.02 	imes 1000 \ m = 20 \ m$.

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