The truth table for the circuit given in the figure is
- A
$A$ $B$ $Y$ $0$ $0$ $1$ $0$ $1$ $0$ $1$ $0$ $0$ $1$ $1$ $0$ - B
$A$ $B$ $Y$ $0$ $0$ $0$ $0$ $1$ $0$ $1$ $0$ $1$ $1$ $1$ $1$ - C
$A$ $B$ $Y$ $0$ $0$ $1$ $0$ $1$ $1$ $1$ $0$ $1$ $1$ $1$ $1$ - D
$A$ $B$ $Y$ $0$ $0$ $1$ $0$ $1$ $1$ $1$ $0$ $0$ $1$ $1$ $0$
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View SolutionFor a $NAND$ gate, the inputs and outputs are given in the table below. The values taken by $C, D, E, F$ are respectively:
Input $A$ Input $B$ Output $Y$ $0$ $1$ $C$ $0$ $0$ $D$ $1$ $0$ $E$ $1$ $1$ $F$
| Input $A$ | Input $B$ | Output $Y$ |
|---|---|---|
| $0$ | $1$ | $C$ |
| $0$ | $0$ | $D$ |
| $1$ | $0$ | $E$ |
| $1$ | $1$ | $F$ |
Boolean algebra is essentially based on
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