The ultimate individual unit of magnetism in any magnet is called

$A$ cylindrical magnetic rod has length $5 \ cm$ and diameter $1 \ cm$. It has uniform magnetization $M = 5.3 \times 10^{3} \ A/m$. Its net magnetic dipole moment is nearly (take $\pi = 22/7$):

If a bar magnet of pole strength $m$ and magnetic moment $M$ is cut equally $5$ times parallel to its axis and again $3$ times perpendicular to its axis, then the pole strength and magnetic moment of each piece are respectively

$A$ bar magnet having centre $O$ has a length of $4 \ cm$. Point $P_1$ is in the broad side-on (equatorial) position and $P_2$ is in the end side-on (axial) position with $OP_1 = OP_2 = 10 \ m$. The ratio of magnetic intensities $H$ at $P_1$ and $P_2$ is:

$A$ cylindrical rod magnet has a length of $5 \, cm$ and a diameter of $1 \, cm$. It has a uniform magnetization of $5.30 \times 10^3 \, A/m$. What is its magnetic dipole moment?

The following figures show the arrangement of bar magnets in different configurations. Each magnet has a magnetic dipole moment $\vec{m}$. Which configuration has the highest net magnetic dipole moment?