The unit J , Pa^{-1} is equivalent to | vedclass

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(A) The unit of energy (work) is Joule $(J)$ and the unit of pressure is Pascal $(Pa)$.Dimensional formula of Joule $(J)$ is $[ML^2T^{-2}]$.Dimensiona

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$m^3$

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(A) The unit of energy (work) is Joule $(J)$ and the unit of pressure is Pascal $(Pa)$.Dimensional formula of Joule $(J)$ is $[ML^2T^{-2}]$.Dimensional formula of Pascal $(Pa)$ is $[ML^{-1}T^{-2}]$.Therefore,the unit $J \, Pa^{-1}$ has dimensions:$\frac{[ML^2T^{-2}]}{[ML^{-1}T^{-2}]} = [L^3]$.Since the dimension $[L^3]$ represents volume,the $SI$ unit is $m^3$.

The unit $J \, Pa^{-1}$ is equivalent to

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