The unit of length convenient on the atomic scale is known as an $\mathring{A}$ and is denoted by $\mathring{A}: 1 \mathring{A} = 10^{-10} \, m$. The size of a hydrogen atom is about $0.5 \mathring{A}$. What is the total atomic volume in $m^{3}$ of a mole of hydrogen atoms?

  • A
    $3.16 \times 10^{-7}$
  • B
    $3.16 \times 10^{-5}$
  • C
    $6.32 \times 10^{-3}$
  • D
    $6.32 \times 10^{-7}$

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Similar Questions

If $\epsilon_0$, $E$, and $t$ represent the free space permittivity, electric field, and time respectively, then the unit of $\frac{\epsilon_0 E}{t}$ will be:

Match List-$I$ with List-$II$:
List-$I$List-$II$
$A$. Coefficient of Viscosity$I$. $[M L^2 T^{-2}]$
$B$. Surface Tension$II$. $[M L^2 T^{-1}]$
$C$. Angular momentum$III$. $[M L^{-1} T^{-1}]$
$D$. Rotational Kinetic energy$IV$. $[M L^0 T^{-2}]$

Match the following (Take the relative strength of the strongest fundamental forces in nature as $1$):
$I$ (Fundamental forces in nature)$II$ (Relative strength)
$(A)$ Strong nuclear force$(e)$ $10^{-2}$
$(B)$ Weak nuclear force$(f)$ $1$
$(C)$ Electromagnetic force$(g)$ $10^{10}$
$(D)$ Gravitational force$(h)$ $10^{-13}$
$(i)$ $10^{-39}$

The correct match is:

In a new system,the unit of mass is $10 \ kg$,the unit of length is $5 \ m$,and the unit of time is $10 \ s$. Then,in this new system,$20 \ g/cm^3$ is equal to:

Match List $I$ with List $II$ and select the correct answer using the codes given below the lists:
List $I$ List $II$
$P.$ Boltzmann constant $1.$ $[ML^2T^{-1}]$
$Q.$ Coefficient of viscosity $2.$ $[ML^{-1}T^{-1}]$
$R.$ Planck constant $3.$ $[MLT^{-3}K^{-1}]$
$S.$ Thermal conductivity $4.$ $[ML^2T^{-2}K^{-1}]$

Codes: $P \quad Q \quad R \quad S$

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