The unit vector in the direction of vec{x} = | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To find the unit vector $\hat{x}$ in the direction of $\vec{x} = (2, 3, \sqrt{3})$,we use the formula $\hat{x} = \frac{\vec{x}}{|\vec{x}|}$.First,

Vedclass · Accepted Answer

$\left(\frac{2}{4}, \frac{3}{4}, \frac{\sqrt{3}}{4}\right)$

Vedclass · Answer

(B) To find the unit vector $\hat{x}$ in the direction of $\vec{x} = (2, 3, \sqrt{3})$,we use the formula $\hat{x} = \frac{\vec{x}}{|\vec{x}|}$.First,calculate the magnitude $|\vec{x}| = \sqrt{2^2 + 3^2 + (\sqrt{3})^2}$.$|\vec{x}| = \sqrt{4 + 9 + 3} = \sqrt{16} = 4$.Now,divide each component of $\vec{x}$ by the magnitude $4$:$\hat{x} = \left(\frac{2}{4}, \frac{3}{4}, \frac{\sqrt{3}}{4}\right)$.Thus,the correct option is $B$.

The unit vector in the direction of $\vec{x} = (2, 3, \sqrt{3})$ is . . . . . . .

Similar Questions

Write all the unit vectors in the $XY$-plane.

If vectors $a$ and $b$ represent two consecutive sides of a regular hexagon,then the vectors representing the remaining four sides in order are:

The vector having magnitude of $2 \sqrt{29}$ units in the direction of vector $\vec{a} = 4 \hat{i} + 3 \hat{j} - 2 \hat{k}$ is . . . . . . .

Let $a$ and $b$ be unit vectors with $\theta$ as the acute angle between them. If $\frac{1}{2}|a-b|=\sin(\lambda \theta)$,then $4 \lambda^2=$

Write two different vectors having the same magnitude.

Vedclass Test Series

Exam Paper Generator

Online Exam Module