The value of frac{sqrt{80}-sqrt{112}}{sqrt{45 | vedclass

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Question

(B) To find the value of the expression $\frac{\sqrt{80}-\sqrt{112}}{\sqrt{45}-\sqrt{63}}$,we simplify the square roots first:$\sqrt{80} = \sqrt{16

Vedclass · Accepted Answer

$1 \frac{1}{3}$

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(B) To find the value of the expression $\frac{\sqrt{80}-\sqrt{112}}{\sqrt{45}-\sqrt{63}}$,we simplify the square roots first:$\sqrt{80} = \sqrt{16 	imes 5} = 4\sqrt{5}$$\sqrt{112} = \sqrt{16 	imes 7} = 4\sqrt{7}$$\sqrt{45} = \sqrt{9 	imes 5} = 3\sqrt{5}$$\sqrt{63} = \sqrt{9 	imes 7} = 3\sqrt{7}$Substituting these values into the expression:$\frac{4\sqrt{5}-4\sqrt{7}}{3\sqrt{5}-3\sqrt{7}} = \frac{4(\sqrt{5}-\sqrt{7})}{3(\sqrt{5}-\sqrt{7})}$Canceling the common term $(\sqrt{5}-\sqrt{7})$ from the numerator and denominator:$= \frac{4}{3} = 1 \frac{1}{3}$

The value of $\frac{\sqrt{80}-\sqrt{112}}{\sqrt{45}-\sqrt{63}}$ is

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