The value of $g$ at a particular point is $9.8\,m/s^2$. Suppose the Earth suddenly shrinks uniformly to half its present size without losing any mass. The value of $g$ at the same point (assuming that the distance of the point from the centre of the Earth does not shrink) will now be ......... $m/s^2$.
- A$4.9$
- B$3.1$
- C$9.8$
- D$19.6$
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Similar Questions
The change in the value of $g$ at a height $h$ above the surface of the earth is the same as at a depth $d$ below the surface of the earth. When both $d$ and $h$ are much smaller than the radius of the earth,then which one of the following is correct?
Medium
View SolutionThe height above the surface of the earth where acceleration due to gravity becomes $\frac{g}{9}$ is ( $R$ is the radius of the earth,$g$ is the acceleration due to gravity at the surface).
The value of acceleration due to gravity at a depth of $ 1600 \,km $ is equal to: (Radius of Earth $ = 6400 \,km $) (in $\,ms^{-2}$)
MediumKCET 2017
View SolutionThe acceleration due to gravity on the surface of Earth is $g$. If the diameter of Earth reduces to half of its original value and mass remains constant,then the acceleration due to gravity on the surface of Earth would be:
DifficultJEE MAIN 2024
View SolutionAn object is taken to a height above the surface of the Earth at a distance of $\frac{5}{4} R$ from the center of the Earth,where the radius of the Earth is $R = 6400 \, km$. The percentage decrease in the weight of the object will be $....\%$.
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