(D) We use the trigonometric reduction formulas:$\cos (270^\circ + \theta ) = \sin \theta$$\cos (90^\circ - \theta ) = \sin \theta$$\sin (270^\circ -

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(D) We use the trigonometric reduction formulas:$\cos (270^\circ + \theta ) = \sin \theta$$\cos (90^\circ - \theta ) = \sin \theta$$\sin (270^\circ - \theta ) = -\cos \theta$Substituting these into the expression:$\sin \theta \cdot \sin \theta - (-\cos \theta ) \cdot \cos \theta$$= \sin^2 \theta + \cos^2 \theta$$= 1$

Class 11 Mathematics Trigonometric Functions Fundamental trigonometrical ratios and functions, Trigonometrical ratio of allied angles

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The value of $\cos (270^\circ + \theta )\cos (90^\circ - \theta ) - \sin (270^\circ - \theta )\cos \theta $ is

A
$0$
B
$-1$
C
$0.5$
D
$1$

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Trigonometric Functions

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Fundamental trigonometrical ratios and functions, Trigonometrical ratio of allied angles

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The value of $\cos (270^\circ + \theta )\cos (90^\circ - \theta ) - \sin (270^\circ - \theta )\cos \theta $ is

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Find the degree measure corresponding to the following radian measure (Use $\pi = \frac{22}{7}$):
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