The value of tan frac{pi}{8} is equal to | vedclass

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(C) We know the formula $	an \frac{	heta}{2} = \frac{\sin 	heta}{1 + \cos 	heta}$.Setting $	heta = \frac{\pi}{4}$,we get $	an \frac{\pi}{8} = \f

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$\frac{1}{\sqrt{2}+1}$

Vedclass · Answer

(C) We know the formula $	an \frac{	heta}{2} = \frac{\sin 	heta}{1 + \cos 	heta}$.Setting $	heta = \frac{\pi}{4}$,we get $	an \frac{\pi}{8} = \frac{\sin(\pi/4)}{1 + \cos(\pi/4)}$.Substituting the values $\sin(\pi/4) = \frac{1}{\sqrt{2}}$ and $\cos(\pi/4) = \frac{1}{\sqrt{2}}$,we have:$	an \frac{\pi}{8} = \frac{1/\sqrt{2}}{1 + 1/\sqrt{2}} = \frac{1/\sqrt{2}}{(\sqrt{2}+1)/\sqrt{2}} = \frac{1}{\sqrt{2}+1}$.

The value of $\tan \frac{\pi}{8}$ is equal to

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