frac{cot x - tan x}{cot 2x} का मान क्या है? | vedclass

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(B) हम जानते हैं कि $\cot x - 	an x = \frac{\cos x}{\sin x} - \frac{\sin x}{\cos x} = \frac{\cos^2 x - \sin^2 x}{\sin x \cos x}$.$\cos 2x = \cos^2 x

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) हम जानते हैं कि $\cot x - 	an x = \frac{\cos x}{\sin x} - \frac{\sin x}{\cos x} = \frac{\cos^2 x - \sin^2 x}{\sin x \cos x}$.$\cos 2x = \cos^2 x - \sin^2 x$ और $\sin 2x = 2 \sin x \cos x$ सर्वसमिका का उपयोग करने पर, हमें प्राप्त होता है $\cot x - 	an x = \frac{\cos 2x}{\frac{1}{2} \sin 2x} = 2 \cot 2x$.अतः, $\frac{\cot x - 	an x}{\cot 2x} = \frac{2 \cot 2x}{\cot 2x} = 2$.

$\frac{\cot x - \tan x}{\cot 2x}$ का मान क्या है?

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