The value of sin ^{-1}(sin 100) + cos ^{-1}(c | vedclass

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(D) We know that $31\pi \approx 31 	imes 3.14159 = 97.389$ and $32\pi \approx 32 	imes 3.14159 = 100.53$. Thus,$31\pi < 100 < 32\pi$.$1$. For $\sin

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$200 - 62\pi$

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(D) We know that $31\pi \approx 31 	imes 3.14159 = 97.389$ and $32\pi \approx 32 	imes 3.14159 = 100.53$. Thus,$31\pi $1$. For $\sin ^{-1}(\sin x)$,since $31\pi So,$\sin ^{-1}(\sin 100) = 100 - 32\pi$.$2$. For $\cos ^{-1}(\cos x)$,since $31\pi $3$. For $	an ^{-1}(	an x)$,since $31\pi So,$	an ^{-1}(	an 100) = 100 - 31\pi$.$4$. For $\cot ^{-1}(\cot x)$,since $31\pi So,$\cot ^{-1}(\cot 100) = 100 - 31\pi$.Summing these: $(100 - 32\pi) + (32\pi - 100) + (100 - 31\pi) + (100 - 31\pi) = 200 - 62\pi$.

The value of $\sin ^{-1}(\sin 100) + \cos ^{-1}(\cos 100) + \tan ^{-1}(\tan 100) + \cot ^{-1}(\cot 100)$ is:

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