The value of acceleration due to gravity at a height of $4 R_E$ from the surface of the Earth is (where $R_E$ is the radius of the Earth and acceleration due to gravity on the surface of the Earth $g = 10 \,ms^{-2}$): (in $\,ms^{-2}$)

  • A
    $0.2$
  • B
    $0.3$
  • C
    $0.4$
  • D
    $3$

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The angular speed with which the earth would have to rotate about its axis so that a person on the equator would weigh $3/5^{th}$ as much as at present is ($g$ = gravitational acceleration, $R$ = equatorial radius of the earth.)

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