The value of current i_{1} flowing from A to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The circuit is a balanced Wheatstone bridge structure. By symmetry,the potential at point $B$ is equal to the potential at point $D$. Since $V_{B}

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(D) The circuit is a balanced Wheatstone bridge structure. By symmetry,the potential at point $B$ is equal to the potential at point $D$. Since $V_{B} = V_{D}$,no current flows through the $5 \Omega$ resistors connected between $B$ and $D$. Thus,the circuit simplifies to two parallel branches between $A$ and $C$. The upper branch consists of two $2 \Omega$ resistors in series,giving $R_{upper} = 2 + 2 = 4 \Omega$. The lower branch consists of two $2 \Omega$ resistors in series,giving $R_{lower} = 2 + 2 = 4 \Omega$. The middle branch consists of two $4 \Omega$ resistors in series,giving $R_{middle} = 4 + 4 = 8 \Omega$. The total resistance $R_{eq}$ of the three parallel branches is $\frac{1}{R_{eq}} = \frac{1}{4} + \frac{1}{4} + \frac{1}{8} = \frac{2+2+1}{8} = \frac{5}{8} \Omega^{-1}$,so $R_{eq} = 1.6 \Omega$. The current $i_{1}$ flows through the middle branch containing $8 \Omega$ resistance. Since the voltage across $A$ and $C$ is $8 V$,the current $i_{1} = \frac{V}{R_{middle}} = \frac{8 V}{8 \Omega} = 1 A$.

The value of current $i_{1}$ flowing from $A$ to $C$ in the circuit diagram is $.......A$

Similar Questions

Resistances are arranged in a cyclic order to form a balanced Wheatstone bridge as shown in the figure. The ratio of power consumed in the branches $(P + Q)$ and $(R + S)$ is

In the following network, the current flowing through $15 \text{ } \Omega$ resistance is (in $\text{ A}$)

What is the value of the current flowing through the galvanometer in the balanced condition of a Wheatstone bridge?

The potential difference $V$ across the filament of the bulb shown in the given Wheatstone bridge varies as $V = i(2i + 1)$,where $i$ is the current in ampere through the filament of the bulb. The emf of the battery $(V_b)$ so that the bridge becomes balanced is (in $V$)

Three resistances $P, Q, R$ each of $2 \,\Omega$ and an unknown resistance $S$ form the four arms of a Wheatstone bridge circuit. When a resistance of $6 \,\Omega$ is connected in parallel to $S$,the bridge gets balanced. What is the value of $S$ in $\Omega$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module