The value of current I in the given current d | vedclass

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(B) According to Kirchhoff's Current Law $(KCL)$,the sum of currents entering a junction equals the sum of currents leaving it.$1$. At the first junct

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$1.5$

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(B) According to Kirchhoff's Current Law $(KCL)$,the sum of currents entering a junction equals the sum of currents leaving it.$1$. At the first junction: The total current entering is $1.2 \ A + 1.0 \ A = 2.2 \ A$. This current flows to the next junction.$2$. At the second junction: The current $2.2 \ A$ enters,and $0.2 \ A$ and $0.1 \ A$ leave. The remaining current flowing forward is $2.2 \ A - (0.2 \ A + 0.1 \ A) = 2.2 \ A - 0.3 \ A = 1.9 \ A$.$3$. At the third junction: The current $1.9 \ A$ enters,and $0.4 \ A$ leaves along one branch. The remaining current $I$ must leave along the other branch. Therefore,$I = 1.9 \ A - 0.4 \ A = 1.5 \ A$.

The value of current $I$ in the given current distribution is: (in $A$)

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