(D) The electric potential $V$ due to an electric dipole at a point defined by position vector $\vec{r}$ is given by the formula:$V = \frac{kp \cos \t

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$k \cdot \frac{\vec{p} \cdot \vec{r}}{r^3}$

(D) The electric potential $V$ due to an electric dipole at a point defined by position vector $\vec{r}$ is given by the formula:$V = \frac{kp \cos \theta}{r^2}$Since the dot product of two vectors $\vec{p}$ and $\vec{r}$ is $\vec{p} \cdot \vec{r} = pr \cos \theta$,we can rewrite the potential as:$V = \frac{k(pr \cos \theta)}{r^3} = \frac{k(\vec{p} \cdot \vec{r})}{r^3}$Therefore,the correct expression is $k \cdot \frac{\vec{p} \cdot \vec{r}}{r^3}$.

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

The value of electric potential at any point due to an electric dipole is

A
$k \cdot \frac{\vec{p} \times \vec{r}}{r^2}$
B
$k \cdot \frac{\vec{p} \times \vec{r}}{r^3}$
C
$k \cdot \frac{\vec{p} \cdot \vec{r}}{r^2}$
D
$k \cdot \frac{\vec{p} \cdot \vec{r}}{r^3}$

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The value of electric potential at any point due to an electric dipole is

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