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(B) $1$. The three capacitors at the bottom left,each of capacitance $C$,are in parallel. Their equivalent capacitance is $C_{p1} = C + C + C = 3C$.$2

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$3\,C$

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(B) $1$. The three capacitors at the bottom left,each of capacitance $C$,are in parallel. Their equivalent capacitance is $C_{p1} = C + C + C = 3C$.$2$. This $3C$ is in series with the capacitor of $3C$ above it. Their equivalent capacitance is $C_{s1} = \frac{3C 	imes 3C}{3C + 3C} = \frac{9C^2}{6C} = 1.5C = \frac{3C}{2}$.$3$. This $\frac{3C}{2}$ is in parallel with the capacitor of $\frac{3C}{2}$ next to it. Their equivalent capacitance is $C_{p2} = \frac{3C}{2} + \frac{3C}{2} = 3C$.$4$. This $3C$ is in series with the top capacitor of $3C$. Their equivalent capacitance is $C_{s2} = \frac{3C 	imes 3C}{3C + 3C} = 1.5C = \frac{3C}{2}$.$5$. Finally,this $\frac{3C}{2}$ is in parallel with the capacitor of $\frac{3C}{2}$ connected directly between $P$ and $Q$. The total equivalent capacitance is $C_{eq} = \frac{3C}{2} + \frac{3C}{2} = 3C$.

The value of equivalent capacitance of the combination shown in the figure between the points $P$ and $Q$ is

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