The value of escape velocity on a certain pla | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The escape velocity $(v_e)$ is given by the formula $v_e = \sqrt{\frac{2GM}{R}}$.The orbital speed $(v_o)$ for a satellite orbiting close to the s

Vedclass · Accepted Answer

$\sqrt{2} \, km/s$

Vedclass · Answer

(C) The escape velocity $(v_e)$ is given by the formula $v_e = \sqrt{\frac{2GM}{R}}$.The orbital speed $(v_o)$ for a satellite orbiting close to the surface is given by $v_o = \sqrt{\frac{GM}{R}}$.By comparing these two expressions,we find the relationship $v_e = \sqrt{2} \cdot v_o$,or $v_o = \frac{v_e}{\sqrt{2}}$.Given $v_e = 2 \, km/s$,we substitute this into the equation:$v_o = \frac{2}{\sqrt{2}} = \sqrt{2} \, km/s$.

The value of escape velocity on a certain planet is $2 \, km/s$. Then the value of orbital speed for a satellite orbiting close to its surface is

Similar Questions

Niche overlap indicates

The glenoid cavity articulates:

Which of the following is $NOT$ included in $In-situ$ conservation?

If the distance of the point $P(1, -2, 1)$ from the plane $x + 2y - 2z = \alpha$,where $\alpha > 0$,is $5$,then the foot of the perpendicular from $P$ to the plane is:

$A$ uniform chain has a mass $m$ and length $l$. It is held on a frictionless table with one-sixth of its length hanging over the edge. The work done in just pulling the hanging part back on the table is

Vedclass Test Series

Exam Paper Generator

Online Exam Module