The Vander Waals equation for 0.5 mol of a g | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The general Vander Waals equation for $n$ moles of a gas is given by: $\left( P + \frac{an^2}{V^2} \right) \left( V - nb \right) = nRT$ Substituti

Vedclass · Accepted Answer

$\left( P + \frac{a}{4V^2} \right) \left( 2V - b \right) = RT$

Vedclass · Answer

(B) The general Vander Waals equation for $n$ moles of a gas is given by: $\left( P + \frac{an^2}{V^2} \right) \left( V - nb \right) = nRT$ Substituting $n = 0.5 = \frac{1}{2}$ mol into the equation: $\left( P + \frac{a(1/2)^2}{V^2} \right) \left( V - \frac{b}{2} \right) = \frac{1}{2} RT$ $\left( P + \frac{a}{4V^2} \right) \left( V - \frac{b}{2} \right) = \frac{RT}{2}$ Multiplying both sides by $2$: $\left( P + \frac{a}{4V^2} \right) \left( 2V - b \right) = RT$

The Vander Waals equation for $0.5 \ mol$ of a gas is:

Similar Questions

Consider the equation $Z = \frac{PV}{RT}.$ Which of the following statements is correct?

For real gases,the relation between $P$,$V$ and $T$ is given by the van der Waals equation,$(P + \frac{an^2}{V^2})(V - nb) = nRT$. For the following gases $CH_4, CO_2, O_2, H_2$,which gas will have $(i)$ highest value of $'a'$ $(ii)$ lowest value of $'b'$?

Between $NH_3$ and $N_2$,which one has a higher value of $(i) \ a$ and which one has a higher value of $(ii) \ b$? (Where $a$ and $b$ are van der Waals constants.)

When does the graph of $p \propto \frac{1}{V}$ not result in a straight line?

In a mole of water vapour at $STP$,the volume actually occupied or taken by the molecules (i.e.,Avogadro's No. $\times$ Volume of one molecule) is

Vedclass Test Series

Exam Paper Generator

Online Exam Module