The vapour density of completely dissociated | vedclass

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(B) The dissociation reaction is: $NH_4Cl(s) \rightleftharpoons NH_3(g) + HCl(g)$.Since the reaction produces $2$ moles of gaseous products from $1$ m

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Half that of $NH_4Cl$

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(B) The dissociation reaction is: $NH_4Cl(s) ightleftharpoons NH_3(g) + HCl(g)$.Since the reaction produces $2$ moles of gaseous products from $1$ mole of solid reactant,the degree of dissociation $\alpha = 1$.The relation between vapour density $(D)$ and molecular weight $(M)$ is $M = 2 	imes D$.The observed molecular weight $(M_{obs})$ is given by $M_{obs} = \frac{M_{theoretical}}{1 + \alpha}$.For complete dissociation,$\alpha = 1$,so $M_{obs} = \frac{M_{theoretical}}{2}$.Since $D \propto M$,the vapour density becomes half of the theoretical vapour density of $NH_4Cl$.

The vapour density of completely dissociated $NH_4Cl$ would be

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