The variation of solubility of four different | vedclass

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(D) According to Henry's law, $p = K_H \chi$, where $K_H$ is Henry's constant and $\chi$ is the mole fraction (solubility).Rearranging the equation, w

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$G_1$

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(D) According to Henry's law, $p = K_H \chi$, where $K_H$ is Henry's constant and $\chi$ is the mole fraction (solubility).Rearranging the equation, we get $\chi = \frac{1}{K_H} p$.This implies that for a given pressure $p$, the solubility $\chi$ is inversely proportional to the Henry's law constant $K_H$.In a plot of $\chi$ versus $p$, the slope of the line is $\frac{1}{K_H}$.$A$ smaller slope indicates a larger value of $K_H$.Since $G_1$ shows the least slope (lowest solubility for a given pressure), $G_1$ has the highest value of Henry's law constant.

Gas	$K_{H} / \text{kbar}$
$Ar$	$40.3$
$CO_{2}$	$1.67$
$HCHO$	$1.83 \times 10^{-5}$
$CH_{4}$	$0.413$

The variation of solubility of four different gases $(G_1, G_2, G_3, G_4)$ in a given solvent with pressure at a constant temperature is shown in the plot (where solubility $\chi$ is plotted on the y-axis and pressure $p$ on the x-axis). The gas with the highest value of Henry's law constant is

Similar Questions

The $K_{H}$ values for some gases at the same temperature '$T$' are given below:

Gas $K_{H} / \text{kbar}$

$Ar$ $40.3$

$CO_{2}$ $1.67$

$HCHO$ $1.83 \times 10^{-5}$

$CH_{4}$ $0.413$

where $K_{H}$ is Henry's Law constant in water. The order of their solubility in water is:

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The solubility of a gas in water depends on

Which of the following laws represents the quantitative relationship between the solubility of gas in liquid and its pressure?

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