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(C) In the velocity-time graph,the slope represents acceleration $(a = dv/dt)$.At point $B$,the slope of the graph is negative,which means the acceler

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there is a force which opposes motion

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(C) In the velocity-time graph,the slope represents acceleration $(a = dv/dt)$.At point $B$,the slope of the graph is negative,which means the acceleration is negative (deceleration).According to Newton's second law of motion,$F = ma$. Since the acceleration is negative,the net force acting on the body must also be negative.$A$ negative force acting on a body moving in a positive direction indicates that the force is opposing the motion of the body.Therefore,at point $B$,there is a force that opposes the motion.

The velocity-time graph of a body is shown in the figure. It implies that at point $B$

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