The voltage drop across the 15, Omega resista | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) First, simplify the circuit. The parallel combination of two $4\, \Omega$ resistors is $2\, \Omega$. The parallel combination of two $8\, \Omega$

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(C) First, simplify the circuit. The parallel combination of two $4\, \Omega$ resistors is $2\, \Omega$. The parallel combination of two $8\, \Omega$ resistors is $4\, \Omega$. The parallel combination of two $12\, \Omega$ resistors is $6\, \Omega$.The upper branch has resistances in series: $2\, \Omega$ (from $4\, \Omega || 4\, \Omega$) + $2\, \Omega$ + $R_{p1}$ (where $R_{p1} = 15\, \Omega || 10\, \Omega = 6\, \Omega$). Total upper branch resistance $R_1 = 2 + 2 + 6 = 10\, \Omega$.The lower branch has resistances in series: $4\, \Omega$ (from $8\, \Omega || 8\, \Omega$) + $6\, \Omega$ (from $12\, \Omega || 12\, \Omega$) = $10\, \Omega$.The two branches are in parallel, so their equivalent resistance is $R_{eq_branches} = (10\, \Omega || 10\, \Omega) = 5\, \Omega$.Total circuit resistance $R_{total} = 5\, \Omega + 1\, \Omega$ (internal) $= 6\, \Omega$.Total current $I = V / R_{total} = 12\, V / 6\, \Omega = 2\, A$.This current splits equally into the two $10\, \Omega$ branches, so $1\, A$ flows through the upper branch.The voltage across the $15\, \Omega || 10\, \Omega$ parallel combination is $V_{AB} = I_{upper} 	imes R_{p1} = 1\, A 	imes 6\, \Omega = 6\, V$.

$A$. Mobility	$P$. $\frac{m}{ne^2 \rho}$
$B$. Electrical conductivity	$Q$. $neAv_{d}$
$C$. Relaxation period	$R$. $\frac{v_{d}}{E}$
$D$. Current	$S$. $\frac{J}{E}$

The voltage drop across the $15\, \Omega$ resistance in the given figure is $.....V.$

Similar Questions

The dimensions of $CV^2$ match with the dimensions of:

Three $60\, W$ light bulbs are mistakenly wired in series and connected to a $120\, V$ power supply. Assume the light bulbs are rated for single connection to $120\, V$. With the mistaken connection,the power dissipated by each bulb is: .................. $W$

$A$ $3\,^oC$ rise in temperature is observed in a conductor by passing a certain current. When the current is doubled,the rise in temperature will be ............. $^oC$.

In a copper voltameter,the mass of copper deposited in $6 \, \text{min}$ is $m \, \text{g}$. If the current-time graph is as shown in the figure,the electrochemical equivalent of copper will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module