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(C) When amplifiers are connected in series, the total voltage gain $(A_v)$ is the product of the individual voltage gains of the amplifiers.Given: $A

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$20 	ext{ mV}$

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(C) When amplifiers are connected in series, the total voltage gain $(A_v)$ is the product of the individual voltage gains of the amplifiers.Given: $A_1 = 8$, $A_2 = 12.5$.Total voltage gain $A_v = A_1 	imes A_2 = 8 	imes 12.5 = 100$.The input signal voltage $V_{in} = 200 \mu V = 200 	imes 10^{-6} 	ext{ V}$.The output voltage $V_{out}$ is given by the formula: $V_{out} = A_v 	imes V_{in}$.$V_{out} = 100 	imes 200 	imes 10^{-6} 	ext{ V} = 20000 	imes 10^{-6} 	ext{ V} = 20 	imes 10^{-3} 	ext{ V}$.Since $10^{-3} 	ext{ V} = 1 	ext{ mV}$, the output voltage is $20 	ext{ mV}$.

The voltage gains of two amplifiers connected in series are $8$ and $12.5$. If the voltage of the input signal is $200 \mu V$, then the voltage of the output signal is

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