(A) The potential difference $V = 4 \times 10^6 \, V$.The charge transferred $Q = 4 \, C$.The time duration $t = 100 \, ms = 100 \times 10^{-3} \, s =

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(A) The potential difference $V = 4 \times 10^6 \, V$.The charge transferred $Q = 4 \, C$.The time duration $t = 100 \, ms = 100 \times 10^{-3} \, s = 0.1 \, s$.The energy delivered $E = V \times Q = 4 \times 10^6 \times 4 = 16 \times 10^6 \, J$.The power $P$ is defined as the rate of energy delivery: $P = \frac{E}{t}$.$P = \frac{16 \times 10^6 \, J}{0.1 \, s} = 160 \times 10^6 \, W$.Since $10^6 \, W = 1 \, MW$,the power is $160 \, MW$.

Class 12 Physics Current Electricity Electrical Energy and Power

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The voltage of clouds is $4 \times 10^6 \, V$ with respect to the ground. In a lightning strike lasting $100 \, ms$,a charge of $4 \, C$ is delivered to the ground. The power of the lightning strike is

AIIMS 2006 All AIIMS

A
$160 \, MW$
B
$80 \, MW$
C
$20 \, MW$
D
$500 \, kW$

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The voltage of clouds is $4 \times 10^6 \, V$ with respect to the ground. In a lightning strike lasting $100 \, ms$,a charge of $4 \, C$ is delivered to the ground. The power of the lightning strike is

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