The volume of gas A is twice that of gas B. T | vedclass

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(B) The compressibility factor $Z$ is defined as $Z = \frac{PV}{nRT}$.Rearranging for pressure,we get $P = \frac{ZnRT}{V}$.At constant temperature $T$

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$2P_A = 3P_B$

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(B) The compressibility factor $Z$ is defined as $Z = \frac{PV}{nRT}$.Rearranging for pressure,we get $P = \frac{ZnRT}{V}$.At constant temperature $T$ and equal number of moles $n$,the pressure $P$ is directly proportional to $\frac{Z}{V}$,i.e.,$P \propto \frac{Z}{V}$.Given $V_A = 2V_B$ and $Z_A = 3Z_B$.Taking the ratio of pressures:$\frac{P_A}{P_B} = \frac{Z_A}{Z_B} 	imes \frac{V_B}{V_A} = \left( \frac{3}{1} ight) 	imes \left( \frac{1}{2} ight) = \frac{3}{2}$.Therefore,$2P_A = 3P_B$.

The volume of gas $A$ is twice that of gas $B$. The compressibility factor of gas $A$ is thrice that of gas $B$ at the same temperature. The ratio of the pressures of the gases for equal number of moles is:

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