The volume strength (in L) of 3 N H_2O_2 is a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The normality $(N)$ of $H_2O_2$ is related to its molarity $(M)$ by the equation: $N = M 	imes n$-factor.For $H_2O_2$,the $n$-factor is $2$,so $M

Vedclass · Accepted Answer

$17$

Vedclass · Answer

(C) The normality $(N)$ of $H_2O_2$ is related to its molarity $(M)$ by the equation: $N = M 	imes n$-factor.For $H_2O_2$,the $n$-factor is $2$,so $M = \frac{N}{2} = \frac{3}{2} = 1.5$ $M$.The volume strength of $H_2O_2$ is given by the formula: $	ext{Volume strength} = M 	imes 11.2$.Therefore,$	ext{Volume strength} = 1.5 	imes 11.2 = 16.8$ $L$.This is approximately $17$ $L$.

The volume strength (in $L$) of $3$ $N$ $H_2O_2$ is approximately

Similar Questions

The strength of $50$ volume solution of hydrogen peroxide is $...... \ g/L$ (Nearest integer). Given: Molar mass of $H_2O_2$ is $34 \ g \ mol^{-1}$. Molar volume of gas at $STP = 22.7 \ L$.

Assertion: Sulfur is oxidized by $H_2O_2$ in the presence of $Fe(III)$.
Reason: $Fe(III)$ catalyzes the oxidation of sulfur to sulfate.

Which of the following statement is/are correct for $H_2O_2$?

$H_2O_2$ is manufactured these days by:

The decomposition of $H_2O_2$ can be prevented by adding which of the following?

Vedclass Test Series

Exam Paper Generator

Online Exam Module