The volumes of 4,N, HCl and 10,N, HCl require | vedclass

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Question

(C) Let $x$ be the volume of $4\,N\, HCl$ required in liters.Then the volume of $10\,N\, HCl$ required is $(1 - x)\, L$.Using the mixture formula $N_1

Vedclass · Accepted Answer

$0.67\, L$ of $4\,N\, HCl$ and $0.33\, L$ of $10\,N\, HCl$

Vedclass · Answer

(C) Let $x$ be the volume of $4\,N\, HCl$ required in liters.Then the volume of $10\,N\, HCl$ required is $(1 - x)\, L$.Using the mixture formula $N_1V_1 + N_2V_2 = N_3V_3$:$4x + 10(1 - x) = 6 	imes 1$$4x + 10 - 10x = 6$$-6x = -4$$x = \frac{4}{6} = 0.67\, L$Thus,the volume of $4\,N\, HCl$ is $0.67\, L$ and the volume of $10\,N\, HCl$ is $1 - 0.67 = 0.33\, L$.

The volumes of $4\,N\, HCl$ and $10\,N\, HCl$ required to make $1\, L$ of $6\,N\, HCl$ are

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