(B) According to Wien's displacement law,the product of the wavelength of maximum energy emission $(\lambda_m)$ and the absolute temperature $(T)$ is

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(B) According to Wien's displacement law,the product of the wavelength of maximum energy emission $(\lambda_m)$ and the absolute temperature $(T)$ is a constant $(b)$: $\lambda_m T = b$ Given: $\lambda_m = 2.93 \times 10^{-10} \ m$ $b = 2.93 \times 10^{-3} \ m \ K$ Substituting the values into the formula: $(2.93 \times 10^{-10} \ m) \times T = 2.93 \times 10^{-3} \ m \ K$ $T = \frac{2.93 \times 10^{-3}}{2.93 \times 10^{-10}} \ K$ $T = 10^7 \ K$ Thus,the maximum temperature attained is of the order of $10^7 \ K$.

Class 11 Physics 2 Thermal Properties of Matter: Heat Transfer Spectral Emissive Power and Wien's Displacement Law

Medium

The wavelength of maximum energy,released during an atomic explosion,was $2.93 \times 10^{-10} \ m$. Given that the Wien's constant is $2.93 \times 10^{-3} \ m \ K$,the maximum temperature attained must be of the order of

A
$10^{-7} \ K$
B
$10^7 \ K$
C
$10^{-13} \ K$
D
$5.86 \times 10^{7} \ K$

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2 Thermal Properties of Matter: Heat Transfer

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Spectral Emissive Power and Wien's Displacement Law

The maximum wavelength of radiation emitted at $2000\;K$ is $4\;\mu m$. What will be the maximum wavelength of radiation emitted at $2400\;K$?

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Three stars $A, B, C$ have surface temperatures $T_{A}, T_{B}, T_{C}$ respectively. Star $A$ appears bluish,star $B$ appears reddish,and star $C$ appears yellowish. Hence,

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Two stars emit maximum radiation at wavelengths $3600 \mathring A$ and $4800 \mathring A$ respectively. The ratio of their temperatures is:

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The maximum energy in thermal radiation from a source occurs at the wavelength $4000 \mathring A$. The effective temperature of the source is ....... $K$.

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The wavelength of maximum intensity of radiation emitted by a star is $289.8 \, nm$. The radiation intensity of the star is (Stefan's constant $\sigma = 5.67 \times 10^{-8} \, W m^{-2} K^{-4}$, Wien's constant $b = 2898 \, \mu m K$).

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The wavelength of maximum energy,released during an atomic explosion,was $2.93 \times 10^{-10} \ m$. Given that the Wien's constant is $2.93 \times 10^{-3} \ m \ K$,the maximum temperature attained must be of the order of

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The maximum wavelength of radiation emitted at $2000\;K$ is $4\;\mu m$. What will be the maximum wavelength of radiation emitted at $2400\;K$?

Three stars $A, B, C$ have surface temperatures $T_{A}, T_{B}, T_{C}$ respectively. Star $A$ appears bluish,star $B$ appears reddish,and star $C$ appears yellowish. Hence,

Two stars emit maximum radiation at wavelengths $3600 \mathring A$ and $4800 \mathring A$ respectively. The ratio of their temperatures is:

The maximum energy in thermal radiation from a source occurs at the wavelength $4000 \mathring A$. The effective temperature of the source is ....... $K$.

The wavelength of maximum intensity of radiation emitted by a star is $289.8 \, nm$. The radiation intensity of the star is (Stefan's constant $\sigma = 5.67 \times 10^{-8} \, W m^{-2} K^{-4}$, Wien's constant $b = 2898 \, \mu m K$).

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