The wavelength of photon A is 400 nm. The fr | vedclass

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(B) $(1)$. Wavelength of $A = 400 \ nm = 400 	imes 10^{-9} \ m$.$(2)$. Wavelength of $B$ $(\lambda) = \frac{c}{
u} = \frac{3 	imes 10^{8} \ m/s}{10

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$B > A > C$

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(B) $(1)$. Wavelength of $A = 400 \ nm = 400 	imes 10^{-9} \ m$.$(2)$. Wavelength of $B$ $(\lambda) = \frac{c}{
u} = \frac{3 	imes 10^{8} \ m/s}{10^{16} \ s^{-1}} = 3 	imes 10^{-8} \ m = 30 \ nm$.$(3)$. Wavelength of $C$ $(\lambda) = \frac{1}{\bar{
u}} = \frac{1}{10^{4} \ cm^{-1}} = 10^{-4} \ cm = 10^{-6} \ m = 1000 \ nm$.Comparing wavelengths: $\lambda_{C} (1000 \ nm) > \lambda_{A} (400 \ nm) > \lambda_{B} (30 \ nm)$.Since Energy $(E) = \frac{hc}{\lambda}$, $E \propto \frac{1}{\lambda}$.Therefore, the order of energy is $E_{B} > E_{A} > E_{C}$.

The wavelength of photon $A$ is $400 \ nm$. The frequency of photon $B$ is $10^{16} \ s^{-1}$. The wave number of photon $C$ is $10^{4} \ cm^{-1}$. The correct order of energy of these photons is:

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