The wavelengths of light absorbed by the comp | vedclass

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Question

(C) The wavelength of light absorbed by a complex is inversely proportional to the crystal field splitting energy $(\Delta_o)$,which in turn depends o

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$\lambda_1 > \lambda_3 > \lambda_2$

Vedclass · Answer

(C) The wavelength of light absorbed by a complex is inversely proportional to the crystal field splitting energy $(\Delta_o)$,which in turn depends on the strength of the ligands.According to the spectrochemical series,the strength of the ligands is $en > H_2O$.Therefore,the crystal field splitting energy follows the order: $[Ni(en)_3]^{2+} > [Ni(H_2O)_4en]^{2+} > [Ni(H_2O)_6]^{2+}$.Since $E = \frac{hc}{\lambda}$,the energy is inversely proportional to the wavelength.Thus,the order of wavelengths absorbed is: $[Ni(H_2O)_6]^{2+} > [Ni(H_2O)_4en]^{2+} > [Ni(en)_3]^{2+}$.This corresponds to $\lambda_1 > \lambda_3 > \lambda_2$.

List-$I$ (Electronic configuration of tetrahedral metal ion)	List-$II$ (Crystal Field Stabilization Energy $(\Delta_t)$)
$A$. $d^2$	$I$. $-0.6$
$B$. $d^4$	$II$. $-0.8$
$C$. $d^6$	$III$. $-1.2$
$D$. $d^8$	$IV$. $-0.4$

The wavelengths of light absorbed by the complexes $[Ni(H_2O)_6]^{2+}$,$[Ni(en)_3]^{2+}$,and $[Ni(H_2O)_4en]^{2+}$ are $\lambda_1$,$\lambda_2$,and $\lambda_3$ respectively. The correct order of wavelengths is:

Similar Questions

Which of the following is the correct order of ligand field strength?

Match the $LIST$-$I$ with $LIST$-$II$:

List-$I$ (Electronic configuration of tetrahedral metal ion) List-$II$ (Crystal Field Stabilization Energy $(\Delta_t)$)

$A$. $d^2$ $I$. $-0.6$

$B$. $d^4$ $II$. $-0.8$

$C$. $d^6$ $III$. $-1.2$

$D$. $d^8$ $IV$. $-0.4$

The complex with the highest magnitude of crystal field splitting energy $\left(\Delta_0\right)$ is

The Crystal Field Stabilisation Energy $(CFSE)$ for $[CoCl_{6}]^{4-}$ is $18000 \; cm^{-1}$. The $CFSE$ for $[CoCl_{4}]^{2-}$ will be $...... \ cm^{-1}$.

Which of the following represents the correct increasing order of crystal field splitting energy?

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