The work done by $6$ moles of helium gas when its temperature increases by $20^{\circ} C$ at constant pressure is (Universal gas constant $R = 8.31 \ J \ mol^{-1} \ K^{-1}$) (in $J$)

An ideal monoatomic gas expands at constant pressure. The work done by the gas on its environment is $200 \,J$, then the heat absorbed by the gas during the process is (in $\,J$)

For an isochoric process,if $T_1 = 27 \, ^\circ C$ and $T_2 = 127 \, ^\circ C$,then $P_1 / P_2 = \dots$

The change in the internal energy of $3$ moles of a gas heated at constant volume from $20^{\circ}C$ to $40^{\circ}C$ is $1080 \ J$. The molar specific heat of the gas at constant volume in $J \ mol^{-1} \ K^{-1}$ is:

In an isobaric process,

The volume $(V)$ of a monatomic gas varies with its temperature $(T)$,as shown in the graph. The ratio of work done by the gas to the heat absorbed by it,when it undergoes a change from state $A$ to state $B$,is