The work function of a metal is 4.2 , eV. If | vedclass

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(C) The work function $\Phi = 4.2 \, eV = 4.2 	imes 1.602 	imes 10^{-19} \, J \approx 6.73 	imes 10^{-19} \, J$. The energy of the incident radiati

Vedclass · Accepted Answer

$3.2 	imes 10^{-19} \, J$

Vedclass · Answer

(C) The work function $\Phi = 4.2 \, eV = 4.2 	imes 1.602 	imes 10^{-19} \, J \approx 6.73 	imes 10^{-19} \, J$. The energy of the incident radiation $E = \frac{hc}{\lambda} = \frac{6.626 	imes 10^{-34} 	imes 3 	imes 10^8}{2000 	imes 10^{-10}} \, J = 9.939 	imes 10^{-19} \, J$. According to Einstein's photoelectric equation,$K_{max} = E - \Phi$. $K_{max} = (9.939 - 6.73) 	imes 10^{-19} \, J = 3.209 	imes 10^{-19} \, J$. Thus,the kinetic energy is approximately $3.2 	imes 10^{-19} \, J$.

The work function of a metal is $4.2 \, eV$. If radiation of $2000 \, \mathring{A}$ falls on the metal,then the kinetic energy of the fastest photoelectron is:

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