The yellow colour solution of Na_2CrO_4 chang | vedclass

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(C) The aqueous solution of sodium chromate $(Na_2CrO_4)$ is yellow due to the presence of chromate ions $(CrO_4^{2-})$. When $CO_2$ gas is passed thr

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$Na_2Cr_2O_7$

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(C) The aqueous solution of sodium chromate $(Na_2CrO_4)$ is yellow due to the presence of chromate ions $(CrO_4^{2-})$. When $CO_2$ gas is passed through this solution,it reacts with water to form carbonic acid $(H_2CO_3)$,which provides $H^+$ ions. The reaction is: $2Na_2CrO_4 + 2CO_2 + H_2O \rightarrow Na_2Cr_2O_7 + 2NaHCO_3$. The formation of sodium dichromate $(Na_2Cr_2O_7)$ results in the orange-red color of the solution due to the presence of dichromate ions $(Cr_2O_7^{2-})$.

The yellow colour solution of $Na_2CrO_4$ changes to orange-red on passing $CO_2$ gas due to the formation of

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Assertion : Solution of $Na_2CrO_4$ in water is intensely coloured.
Reason : Oxidation state of $Cr$ in $Na_2CrO_4$ is $+VI$.

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