The Young's modulus of a rubber string 8, cm | vedclass

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(B) The elongation $\Delta L$ of a string of length $L$,density $d$,and Young's modulus $Y$ due to its own weight is given by the formula: $\Delta L =

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$9.6 	imes 10^{-11}\, m$

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(B) The elongation $\Delta L$ of a string of length $L$,density $d$,and Young's modulus $Y$ due to its own weight is given by the formula: $\Delta L = \frac{L^2 dg}{2Y}$.Given values are: $L = 8\, cm = 8 	imes 10^{-2}\, m$,$d = 1.5\, kg/m^3$,$Y = 5 	imes 10^8\, N/m^2$,and $g = 9.8\, m/s^2$.Substituting these values into the formula:$\Delta L = \frac{(8 	imes 10^{-2})^2 	imes 1.5 	imes 9.8}{2 	imes 5 	imes 10^8}$$\Delta L = \frac{64 	imes 10^{-4} 	imes 14.7}{10^9}$$\Delta L = \frac{940.8 	imes 10^{-4}}{10^9} = 940.8 	imes 10^{-13} = 9.408 	imes 10^{-11}\, m$.Rounding to the nearest provided option,the result is $9.6 	imes 10^{-11}\, m$.

The Young's modulus of a rubber string $8\, cm$ long and density $1.5\, kg/m^3$ is $5 \times 10^8\, N/m^2$. If it is suspended from the ceiling in a room,the increase in length due to its own weight will be:

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