The zero of the linear polynomial $p(x) = 3x - 6$ is $\ldots$

The zeros of the cubic polynomial $p(x) = ax^3 + bx^2 + cx + d$ where $a \neq 0$ and $a, b, c, d \in R$ are $\alpha, \beta,$ and $\gamma$. Then $\alpha \beta \gamma = \dots$

Are the following statements 'True' or 'False'? Justify your answers.
If all three zeroes of a cubic polynomial $x^{3}+ax^{2}-bx+c$ are positive,then at least one of $a, b$ and $c$ is non-negative.

The value of $p(x) = 4x^3 + 3x^2 + 2x + 1$ at $x = 1$ is $\ldots \ldots \ldots$

Find the zeros of the following quadratic polynomial: $p(x) = 3x^2 + 15x$. (in $, -5$)

If the zeroes of the quadratic polynomial $ax^{2} + bx + c, c \neq 0$ are equal,then