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(A) The mutual inductance $M$ of the system of two coils is defined by the relationship between the flux through one coil and the current in the other

Vedclass · Accepted Answer

$5 	imes 10^{-3} \ Wb$

Vedclass · Answer

(A) The mutual inductance $M$ of the system of two coils is defined by the relationship between the flux through one coil and the current in the other.Given: When $I_A = 2 \ A$,$\phi_B = 10^{-2} \ Wb$.The mutual inductance $M_{BA}$ is given by $M_{BA} = \frac{\phi_B}{I_A} = \frac{10^{-2}}{2} = 5 	imes 10^{-3} \ H$.According to the principle of reciprocity,$M_{AB} = M_{BA} = 5 	imes 10^{-3} \ H$.Now,when $I_A = 0$ and $I_B = 1 \ A$,the flux through coil $A$ is given by $\phi_A = M_{AB} 	imes I_B$.Substituting the values: $\phi_A = (5 	imes 10^{-3} \ H) 	imes (1 \ A) = 5 	imes 10^{-3} \ Wb$.

There are two coils $A$ and $B$ separated by some distance. If a current of $2 \ A$ flows through $A$,a magnetic flux of $10^{-2} \ Wb$ passes through $B$ (no current through $B$). If no current passes through $A$ and a current of $1 \ A$ passes through $B$,what is the flux through $A$?

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