There are two electric bulbs,(i) marked 60, W | vedclass

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(A) We know that the formula for resistance is $R = \frac{V^2}{P}$,where $V$ is the voltage and $P$ is the power.Since both bulbs are rated for the sa

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$60\, W$ bulb

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(A) We know that the formula for resistance is $R = \frac{V^2}{P}$,where $V$ is the voltage and $P$ is the power.Since both bulbs are rated for the same voltage $(V = 220\, V)$,the resistance $R$ is inversely proportional to the power $P$ $(R \propto \frac{1}{P})$.Therefore,the bulb with the lower power rating will have a higher resistance.Comparing the two bulbs,the $60\, W$ bulb has a lower power rating than the $100\, W$ bulb.Thus,the $60\, W$ bulb has higher resistance.

There are two electric bulbs,$(i)$ marked $60\, W, 220\, V$ and $(ii)$ marked $100\, W, 220\, V$. Which one of them has higher resistance?

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