There are two equipotential surfaces as shown in the figure. The distance between them is $r$. If a charge of $-q \text{ C}$ is moved from surface $A$ to surface $B$,the resultant work done will be:

  • A
    $W = \frac{1}{4\pi \varepsilon_0} \frac{q}{r}$
  • B
    $W = \frac{1}{4\pi \varepsilon_0} \frac{q}{r^2}$
  • C
    $W = -\frac{1}{4\pi \varepsilon_0} \frac{q}{r^2}$
  • D
    $W = 0$

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