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(C) Efficiency of pipe $A = \frac{1}{16}$ tank per hour.Efficiency of pipe $B = \frac{1}{10}$ tank per hour.In a cycle of $2 	ext{ h}$ (first $A$ for

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$12 \frac{2}{5} 	ext{ h}$

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(C) Efficiency of pipe $A = \frac{1}{16}$ tank per hour.Efficiency of pipe $B = \frac{1}{10}$ tank per hour.In a cycle of $2 	ext{ h}$ (first $A$ for $1 	ext{ h}$,then $B$ for $1 	ext{ h}$),the part of the tank filled is $\frac{1}{16} + \frac{1}{10} = \frac{5+8}{80} = \frac{13}{80}$.In $6$ such cycles $(12 	ext{ h})$,the part filled is $6 	imes \frac{13}{80} = \frac{78}{80} = \frac{39}{40}$.Remaining part of the tank $= 1 - \frac{39}{40} = \frac{1}{40}$.Now,it is the turn of pipe $A$ to fill the remaining part.Time taken by $A$ to fill $\frac{1}{40}$ part $= \frac{1/40}{1/16} = \frac{16}{40} = \frac{2}{5} 	ext{ h}$.Total time taken $= 12 	ext{ h} + \frac{2}{5} 	ext{ h} = 12 \frac{2}{5} 	ext{ h}$.

There are two inlets $A$ and $B$ connected to a tank. $A$ and $B$ can fill the tank in $16 \text{ h}$ and $10 \text{ h}$,respectively. If both the pipes are opened alternately for $1 \text{ h}$,starting with $A$,then how much time will the tank take to be filled?

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