There is a 60 % increase in an amount in 6 ye | vedclass

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(C) Simple Interest ($S$.$I$.) for $6$ years $= 0.6P$. Since $S.I. = \frac{P 	imes R 	imes T}{100}$,we have $0.6P = \frac{P 	imes R 	imes 6}{100}$

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$3972$

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(C) Simple Interest ($S$.$I$.) for $6$ years $= 0.6P$. Since $S.I. = \frac{P 	imes R 	imes T}{100}$,we have $0.6P = \frac{P 	imes R 	imes 6}{100}$. Solving for $R$,we get $R = \frac{0.6 	imes 100}{6} = 10 \% 	ext{ per annum}$. Now,we calculate the Compound Interest ($C$.$I$.) for $P = ₹ 12000$,$R = 10 \%$,and $T = 3$ years. $C.I. = P \left[ \left( 1 + \frac{R}{100} ight)^T - 1 ight]$. $C.I. = 12000 \left[ \left( 1 + \frac{10}{100} ight)^3 - 1 ight] = 12000 \left[ (1.1)^3 - 1 ight]$. $C.I. = 12000 	imes (1.331 - 1) = 12000 	imes 0.331 = ₹ 3972$.

There is a $60 \%$ increase in an amount in $6$ years at simple interest. What will be the compound interest (in ₹) of ₹ $12000$ after $3$ years at the same rate?

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