There is a current of 1.344 , A in a copper w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The formula for drift velocity is given by $v_d = \frac{I}{nAe}$.Given:$I = 1.344 \, A$$A = 1 \, mm^2 = 10^{-6} \, m^2$$n = 8.4 	imes 10^{22} \,

Vedclass · Accepted Answer

$0.1 \, mm/s$

Vedclass · Answer

(C) The formula for drift velocity is given by $v_d = \frac{I}{nAe}$.Given:$I = 1.344 \, A$$A = 1 \, mm^2 = 10^{-6} \, m^2$$n = 8.4 	imes 10^{22} \, 	ext{electrons}/cm^3 = 8.4 	imes 10^{28} \, 	ext{electrons}/m^3$$e = 1.6 	imes 10^{-19} \, C$Substituting these values into the formula:$v_d = \frac{1.344}{(8.4 	imes 10^{28}) 	imes (10^{-6}) 	imes (1.6 	imes 10^{-19})}$$v_d = \frac{1.344}{8.4 	imes 1.6 	imes 10^3}$$v_d = \frac{1.344}{13.44 	imes 10^3} = 0.1 	imes 10^{-3} \, m/s$$v_d = 0.1 \, mm/s$.

There is a current of $1.344 \, A$ in a copper wire whose area of cross-section normal to the length of the wire is $1 \, mm^2$. If the number of free electrons per $cm^3$ is $8.4 \times 10^{22}$, then the drift velocity would be

Similar Questions

$A$ current $I$ flows through a uniform wire of diameter $d$,when the mean drift velocity is $v_d$. The same current will flow through a wire of diameter $d/2$ made of the same material,if the mean drift velocity of the electrons is

$A$ current passes through a wire of nonuniform cross-section. Which of the following quantities are independent of the cross-section?

There is a current of $40 \ A$ in a wire of cross-sectional area $10^{-6} \ m^2$. If the number of free electrons per $m^3$ is $10^{29}$,then the drift velocity will be:

$A$ metallic block has no potential difference applied across it. What is the mean velocity of free electrons in terms of $T$ (absolute temperature of the block)?

$A$ potential difference is applied across the ends of a metallic wire. If the potential difference is doubled,then the drift velocity

Vedclass Test Series

Exam Paper Generator

Online Exam Module