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(B) The sides of the triangular wall are $a = 15 \, m$,$b = 11 \, m$,and $c = 6 \, m$.First,we calculate the semi-perimeter $(s)$:$s = \frac{a + b + c

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$20 \sqrt{2} \, m^2$

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(B) The sides of the triangular wall are $a = 15 \, m$,$b = 11 \, m$,and $c = 6 \, m$.First,we calculate the semi-perimeter $(s)$:$s = \frac{a + b + c}{2} = \frac{15 + 11 + 6}{2} \, m = \frac{32}{2} \, m = 16 \, m$.Now,using Heron's formula,the area of the triangular surface is:Area $= \sqrt{s(s - a)(s - b)(s - c)}$$= \sqrt{16(16 - 15)(16 - 11)(16 - 6)} \, m^2$$= \sqrt{16 	imes 1 	imes 5 	imes 10} \, m^2$$= \sqrt{16 	imes 50} \, m^2$$= \sqrt{800} \, m^2$$= \sqrt{400 	imes 2} \, m^2 = 20 \sqrt{2} \, m^2$.Thus,the required area painted in colour is $20 \sqrt{2} \, m^2$.

There is a slide in a park. One of its side walls has been painted in some colour with a message "$KEEP$ $THE$ $PARK$ $GREEN$ $AND$ $CLEAN$". If the sides of the wall are $15 \, m$,$11 \, m$ and $6 \, m$,find the area painted in colour.

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